How do you find the Least common multiple of #10ba, 20ba, 28ba#?
140ba
All of them share ba, so all you have to do is locate LCD for 10, 20, and 28.
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To find the least common multiple (LCM) of (10ba), (20ba), and (28ba), we first need to factor each expression into its prime factors. Then, we take the highest power of each prime factor that appears in any of the expressions.
The prime factorization of (10ba) is (2 \times 5 \times b \times a). The prime factorization of (20ba) is (2^2 \times 5 \times b \times a). The prime factorization of (28ba) is (2^2 \times 7 \times b \times a).
Taking the highest power of each prime factor, we have (2^2), (5^1), and (7^1).
Therefore, the LCM of (10ba), (20ba), and (28ba) is (2^2 \times 5^1 \times 7^1 \times b \times a), which simplifies to (140ba).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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