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How do you find the LCM of #(5m+15), (2m+6)#?

Answer 1

Eli Assouline

#= 10(m+3)#

Factorise each of the expressions first:

#5(m+3) and 2(m+3)#

The LCM is made up of all the factors, without duplicates:

#LCM = 2*5(m+3)#

#= 10(m+3)#

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Answer 2

Julia Adams

To find the least common multiple (LCM) of (5m+15) and (2m+6), we need to factorize both expressions and then find the product of the highest powers of all the factors.

First, let's factorize (5m+15): 5m+15 = 5(m+3)

Next, let's factorize (2m+6): 2m+6 = 2(m+3)

Now, we can see that both expressions have the factor (m+3). To find the LCM, we take the product of the highest powers of all the factors: LCM = 5 * 2 * (m+3)

Therefore, the LCM of (5m+15) and (2m+6) is 10(m+3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.