How do you find the LCM for #2r+2#, #r^2+r# and #r+1#?

Answer 1

#color(maroon)(L C M = 2r * (r + 1)#

#2r + 2 = 2 * (r + 1)#
#r^2 + r = r * (r + 1)#
#"Three terms are " 2* (r + 1), r * (r + 1), 1 * (r + 1)#

#"since " (r + 1) " is common in all the three terms",

#:. L C M = (r + 1) * 2 * r * 1 = 2r * (r + 1)#
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Answer 2

To find the least common multiple (LCM) for the expressions 2r+2, r^2+r, and r+1, we need to factorize each expression and then determine the highest power of each factor that appears in any of the expressions.

The factorization of 2r+2 is 2(r+1), the factorization of r^2+r is r(r+1), and the factorization of r+1 is (r+1).

Now, we consider the highest power of each factor:

  • The highest power of 2 is 1,
  • The highest power of r is 1,
  • The highest power of (r+1) is 1.

Therefore, the LCM of 2r+2, r^2+r, and r+1 is 2(r+1)(r).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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