How do you find the LCD for #2x(x-1) , x^2- 1 , 4#?

Answer 1

#LCD=4x(x^2-1)#

The given terms are #2x(x-1), (x^2-1),4# Factors of each term : #2x(x-1)=2*x*(x-1)# #(x^2-1)=(x+1)(x-1)# #4# #LCD=4*(x+1)(x-1)*x=4x(x^2-1)#
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Answer 2

To find the least common denominator (LCD) for the given expressions, we need to factor each expression completely.

The expression 2x(x-1) is already factored completely.

The expression x^2 - 1 can be factored as (x+1)(x-1).

The expression 4 is already factored completely as well.

Now, we need to identify the common factors among the expressions. In this case, the common factors are (x-1) and (x+1).

To find the LCD, we multiply all the common factors and any remaining factors together.

Therefore, the LCD for 2x(x-1), x^2 - 1, and 4 is 4(x-1)(x+1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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