How do you find the inverse of #y=log_8x#?

Answer 1

To find the inverse of ( y = \log_8 x ), we switch the roles of ( x ) and ( y ) and solve for ( y ):

  1. Rewrite the equation as ( x = \log_8 y ).
  2. Rewrite the logarithmic equation in exponential form: ( 8^x = y ).
  3. Swap ( x ) and ( y ) to get the inverse function: ( y = 8^x ).

So, the inverse of ( y = \log_8 x ) is ( y = 8^x ).

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Answer 2

# f^-1(x) = 8^x #

To find the inverse function the subject of the formula is

changed to x.

Using: # log_b a = n rArr a = b^n #
then # log_8 x = y rArr x = 8^y #
# rArr f^-1(x) = 8^x #
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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