How do you find the inverse of #y=log_8(x+2)#?
To find the inverse of the function y = log_8(x + 2), we switch the roles of x and y and then solve for the new y.

Start with the original equation: y = log_8(x + 2).

Switch x and y: x = log_8(y + 2).

Rewrite the logarithmic equation in exponential form: 8^x = y + 2.

Solve for y: y = 8^x  2.
So, the inverse of y = log_8(x + 2) is y = 8^x  2.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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