How do you find the inverse of #y=log_8(x+2)#?

Answer 1

To find the inverse of the function y = log_8(x + 2), we switch the roles of x and y and then solve for the new y.

  1. Start with the original equation: y = log_8(x + 2).

  2. Switch x and y: x = log_8(y + 2).

  3. Rewrite the logarithmic equation in exponential form: 8^x = y + 2.

  4. Solve for y: y = 8^x - 2.

So, the inverse of y = log_8(x + 2) is y = 8^x - 2.

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Answer 2

#y=8^x-2#

Given:

#y=log_8(x+2)#

Write as

#8^y=x+2#
#x=8^y-2#

Now swap the letters round:

#y=8^x-2#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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