# How do you find the inverse of #y=log( -3x) +2#?

To find the inverse of ( y = \log(-3x) + 2 ), follow these steps:

- Replace ( y ) with ( x ) and ( x ) with ( y ).
- Solve for ( y ).

So, the inverse function is ( x = \log(-3y) + 2 ). To solve for ( y ), first isolate the logarithmic term, then take the exponential of both sides.

Here's the process:

- Subtract 2 from both sides to isolate the logarithmic term: ( x - 2 = \log(-3y) ).
- Rewrite the equation in exponential form: ( -3y = 10^{x - 2} ).
- Divide both sides by -3: ( y = -\frac{1}{3} \cdot 10^{x - 2} ).

So, the inverse function is ( y = -\frac{1}{3} \cdot 10^{x - 2} ).

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Have you have used the word 'log' I am assuming you are talking about

Given:

Note that

Now swap the letters

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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