# How do you find the inverse of # (x + 2)^2 - 4# and is it a function?

The inverse of a function is found algebraiccally by switching the x and y values.

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To find the inverse of ( (x + 2)^2 - 4 ), follow these steps:

- Replace ( f(x) ) with ( y ).
- Swap the roles of ( x ) and ( y ).
- Solve the resulting equation for ( y ) to get the inverse function.

So, starting with ( y = (x + 2)^2 - 4 ):

[ x = (y + 2)^2 - 4 ] [ x + 4 = (y + 2)^2 ] [ \sqrt{x + 4} = y + 2 ] [ y = \sqrt{x + 4} - 2 ]

Therefore, the inverse of ( (x + 2)^2 - 4 ) is ( \sqrt{x + 4} - 2 ).

Regarding whether it's a function, yes, it is a function because for each input ( x ), there is exactly one output ( y ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you find the inverse of #f^-1(x)= -2 - 1/(x-1)#?
- What are the asymptotes for #F(X) = (1/ X^2) - 2#?

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