# How do you find the inverse of #p(x)=x^3-3x^2+3x-1#?

To find the inverse of ( p(x) = x^3 - 3x^2 + 3x - 1 ), follow these steps:

- Replace ( p(x) ) with ( y ).
- Swap ( x ) and ( y ) to get ( x = y^3 - 3y^2 + 3y - 1 ).
- Rearrange the equation to solve for ( y ).
- Solve the cubic equation for ( y ).
- The resulting expression is the inverse function.

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Find

#p^(-1)(y) = root(3)(y)+1#

Taking the cube root of both ends we find:

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you identify all horizontal and slant asymptote for #f(x)=2+5/(x^2+2)#?

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