How do you find the inverse of #log 2^-x#?

Answer 1

To find the inverse of the function ( \log_{2}^{-x} ), first, express the function in exponential form. Then interchange the roles of ( x ) and ( y ) and solve for ( y ) to find the inverse function.

Given: [ \log_{2}^{-x} ]

Express it in exponential form: [ 2^y = -x ]

Interchange ( x ) and ( y ): [ 2^x = -y ]

Solve for ( y ): [ y = -2^x ]

So, the inverse of the function ( \log_{2}^{-x} ) is ( y = -2^x ).

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Answer 2

Step by Step process is given below.

#y=log(2^(-x))#

Note (x,y) inverse is (y,x) to get the inverse function we need to do the following steps.

#1.# swap #x # and # y# #x=log(2^(-y))#
#2.# solve for #y#
#x=-y*log(2)# using #log(a^n) = nlog(a)# #-x=log(2)y# #-x/log(2) =y#
The inverse function is #f^-1(x) = -x/log(2)#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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