# How do you find the inverse of #f(x)=x/(x+9)#?

To find the inverse of (f(x) = \frac{x}{x + 9}), follow these steps:

- Replace (f(x)) with (y): (y = \frac{x}{x + 9}).
- Swap (x) and (y): (x = \frac{y}{y + 9}).
- Solve for (y): [x(y + 9) = y] [xy + 9x = y] [xy - y = -9x] [y(x - 1) = -9x] [y = \frac{-9x}{x - 1}]

So, the inverse function is (f^{-1}(x) = \frac{-9x}{x - 1}).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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