How do you find the inverse of #f(x)= -|x+1|+4#?
The function
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To find the inverse of ( f(x) = -|x+1| + 4 ):
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Replace ( f(x) ) with ( y ): ( y = -|x+1| + 4 ).
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Swap ( x ) and ( y ): ( x = -|y+1| + 4 ).
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Solve for ( y ):
- Subtract 4 from both sides: ( x - 4 = -|y+1| ).
- Multiply both sides by -1: ( 4 - x = |y+1| ).
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Solve for ( |y+1| ):
- If ( 4 - x \geq 0 ), then ( 4 - x = y + 1 ).
- Subtract 1 from both sides: ( 3 - x = y ).
- If ( 4 - x < 0 ), then ( 4 - x = -(y + 1) ).
- Multiply both sides by -1: ( x - 4 = y + 1 ).
- Subtract 1 from both sides: ( x - 5 = y ).
- If ( 4 - x \geq 0 ), then ( 4 - x = y + 1 ).
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Combine both cases:
- ( y = \begin{cases} 3 - x & \text{if } x \leq 4 \ x - 5 & \text{if } x > 4 \end{cases} ).
Therefore, the inverse function is ( f^{-1}(x) = \begin{cases} 3 - x & \text{if } x \leq 4 \ x - 5 & \text{if } x > 4 \end{cases} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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