# How do you find the inverse of #f (x) = 1/3 x +2 #?

To find the inverse of ( f(x) = \frac{1}{3}x + 2 ), follow these steps:

- Start with the function ( f(x) = \frac{1}{3}x + 2 ).
- Replace ( f(x) ) with ( y ), so the equation becomes ( y = \frac{1}{3}x + 2 ).
- Swap ( x ) and ( y ) to change the equation to ( x = \frac{1}{3}y + 2 ).
- Solve for ( y ) in terms of ( x ): [ x = \frac{1}{3}y + 2 ] [ x - 2 = \frac{1}{3}y ] [ 3(x - 2) = y ] [ y = 3x - 6 ]
- Replace ( y ) with ( f^{-1}(x) ), so the inverse function is ( f^{-1}(x) = 3x - 6 ).

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