How do you find the inverse of #2x + 3y = 6#?

Answer 1

#2y + 3x = 6#

To find the inverse simply switch x and y. #2x+3y=6#

switch x and y...

#2y + 3x = 6#

If you need this in another form...

#2y= 6-3x#
#y= -3/2x + 3#
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Answer 2

To find the inverse of the equation (2x + 3y = 6), follow these steps:

  1. Rewrite the equation, solving for (y): [ 2x + 3y = 6 ] [ 3y = 6 - 2x ] [ y = \frac{6 - 2x}{3} ]

  2. Swap (x) and (y): [ x = \frac{6 - 2y}{3} ]

  3. Solve this equation for (y): [ 3x = 6 - 2y ] [ 3x - 6 = -2y ] [ -3x + 6 = 2y ] [ y = \frac{-3x + 6}{2} ]

So, the inverse of (2x + 3y = 6) is ( y = \frac{-3x + 6}{2} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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