How do you find the inverse of #2x + 3y = 6#?
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To find the inverse of the equation (2x + 3y = 6), follow these steps:

Rewrite the equation, solving for (y): [ 2x + 3y = 6 ] [ 3y = 6  2x ] [ y = \frac{6  2x}{3} ]

Swap (x) and (y): [ x = \frac{6  2y}{3} ]

Solve this equation for (y): [ 3x = 6  2y ] [ 3x  6 = 2y ] [ 3x + 6 = 2y ] [ y = \frac{3x + 6}{2} ]
So, the inverse of (2x + 3y = 6) is ( y = \frac{3x + 6}{2} ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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