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How do you find the intercepts of # 4y = 2x +6#?

Answer 1

Eva Abramson

# x= -3 and y = 3/2#

A line has an x-intercept and a y-intercept, the points where it crosses the x-axis and the y-axis respectively.

On the y-axis, #x = 0 # and on the x-axis, #y = 0.#

In #4y = 2x +6#

To find the y-intercept , make #x=0#

#4y = 0 +6" "rArr y = 6/4 = 3/2#

To find the x-intercept , make #y=0#

#0 = 2x +6" " rArr 2x =-6 " " rArr x = -3#

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Answer 2

Hazel Anglin

To find the intercepts of the equation (4y = 2x + 6), you can set one of the variables to zero and solve for the other variable. To find the y-intercept, set (x) to zero and solve for (y). To find the x-intercept, set (y) to zero and solve for (x).

For the y-intercept: [4y = 2(0) + 6] [4y = 6] [y = \frac{6}{4} = \frac{3}{2}]

For the x-intercept: [4(0) = 2x + 6] [0 = 2x + 6] [-6 = 2x] [x = -3]

So, the y-intercept is ((0, \frac{3}{2})) and the x-intercept is ((-3, 0)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.