How do you find the intercepts for #y=x+2#?

Answer 1

The x-intercept is #-2#.
The y-intercept is #2#.

The equation #y=x+2#, which is the slope-intercept form for a linear equation #y=mx+b#, where #m# is the slope, and #b# is the y-intercept. Therefore the y-intercept for #y=x+2# is #2#.
The x-intercept is the value of #x# when #y=0#.
#0=x+2#
#-2=x#
#x=-2#
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Answer 2

To find the intercepts for the equation ( y = x + 2 ), you set either ( x = 0 ) to find the y-intercept or ( y = 0 ) to find the x-intercept.

For the y-intercept, substitute ( x = 0 ) into the equation:
( y = 0 + 2 = 2 )
So, the y-intercept is (0, 2).

For the x-intercept, substitute ( y = 0 ) into the equation:
( 0 = x + 2 )
Solve for ( x ):
( x = -2 )
So, the x-intercept is (-2, 0).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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