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How do you find the intercepts for #y= -3x+6#?

Answer 1

#y=6# (y-intercept)
#x=2# (x-intercept)

Since the linear equation is in the form #y=mx+b#, we know the y-intercept is #x=6#. We can find the x-intercept by setting #y# to #0#. #0=-3x+6# #3x=6# #x=2#

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Answer 2

Eva Abramson

To find the intercepts for the equation ( y = -3x + 6 ), you set ( x ) or ( y ) to zero and solve for the other variable.

For the ( x )-intercept, ( y ) is set to zero: [ 0 = -3x + 6 ] [ 3x = 6 ] [ x = 2 ]

So the ( x )-intercept is ( (2, 0) ).

For the ( y )-intercept, ( x ) is set to zero: [ y = -3(0) + 6 ] [ y = 6 ]

So the ( y )-intercept is ( (0, 6) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.