How do you find the intercepts for #y=2x^25x+2#?
(2x+1) (x2)
Ok so I know the picture is a little hard to read as this was done on my doodle pad.
However, here is a written expression.
First, divide a and c which would be 2 and 2. Then, find two numbers that multiply 4 and add 5 which would be 1 and 4. Next, split the middle with 2x^24x1x+2.
This part's a little tricky, but hang in there :)
Ok, so factor out a 2x from the 2x^2 and a 1 from 1x+2, both answers should be (x2)
Now this a little hard to explain, but since you used both 2x and 1 to divide 2x^24x1x+2, write (2x1).
Now your final answers should be (2x1) (x2)
Going further to find your xintercepts, set each equation to zero.
2x1=0 is x=1/2 x2=0 is x=2
Your x intercepts are 1/2 and 2.
Hope this helped! :)
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To find the intercepts for the equation y = 2x^2  5x + 2, you set y to 0 to find the xintercepts, and set x to 0 to find the yintercept.

To find the xintercepts, solve the equation 2x^2  5x + 2 = 0 for x using factoring, the quadratic formula, or completing the square.

To find the yintercept, substitute x = 0 into the equation y = 2x^2  5x + 2 and solve for y.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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