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How do you find the intercepts for #2x-4y=12#?

Answer 1

Nathan Axel

You find the #y#-intercept by setting #x=0# and vice versa.
But you may first divide everything by #2#

#->x-2y=6#

#y#-intercept: #0-4y=12->y=12/-4=-3->(0,-3)#

#x#-intercept: #x-2*0=6->x=6->(6,0)# graph{0.5*x-3 [-6.04, 13.96, -6.88, 3.12]}

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Answer 2

Savannah Anderson

To find the intercepts for the equation 2x - 4y = 12, set one variable to zero at a time and solve for the other variable.

To find the x-intercept, set y = 0 and solve for x: 2x - 4(0) = 12 2x = 12 x = 12 / 2 x = 6

So, the x-intercept is (6, 0).

To find the y-intercept, set x = 0 and solve for y: 2(0) - 4y = 12 -4y = 12 y = 12 / -4 y = -3

So, the y-intercept is (0, -3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.