# How do you find the integral of #(x^2)/(16-x^2)^(1/2)#?

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To find the integral of (x^2)/(16-x^2)^(1/2), you can use the trigonometric substitution method. Let x = 4sin(θ). Then, dx = 4cos(θ) dθ. Substitute these expressions into the integral. After simplifying, the integral transforms into ∫16sin^2(θ) dθ. You can simplify this further using the identity sin^2(θ) = (1 - cos(2θ))/2. After integrating term by term, the result will involve trigonometric functions, and you can then convert back to the original variable x to obtain the final answer.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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