# How do you find the integral of #int (x+5)/(sqrt(9-(x-3)^2)#?

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To find the integral of (\int \frac{x+5}{\sqrt{9-(x-3)^2}}), you can use a trigonometric substitution. Let (x-3 = 3\sin(\theta)), which implies (x = 3\sin(\theta) + 3) and (dx = 3\cos(\theta) d\theta). Then substitute these expressions into the integral and simplify. This substitution transforms the integral into one that can be evaluated using trigonometric identities.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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