# How do you find the integral of #int 5/sqrt(9-x^2)dx#?

We have that

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Please see the explanation.

You can find the general form of the integral in any list of integrals:

However, I think you want to be shown how to do the trigonometric substitution that put this general form on the list. Let's begin:

Substitute the above into the integral:

Factor 9 from under the radical:

The numerator and denominator cancel to become 1:

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