# How do you find the integral of #int 1/sqrt(1-(x+1)^2)dx#?

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To find the integral of ( \frac{1}{\sqrt{1 - (x+1)^2}} ), use the trigonometric substitution ( x + 1 = \sin(\theta) ) and ( dx = \cos(\theta) d\theta ). Then proceed with the substitution and integrate accordingly.

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