# How do you find the integral of #int 1/(4+(x-1)^2)dx#?

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To find the integral of ( \frac{1}{4+(x-1)^2} ), you can use the trigonometric substitution method. Let ( x - 1 = 2 \tan(\theta) ), then ( dx = 2 \sec^2(\theta) d\theta ). Substitute these expressions into the integral and simplify. You will end up with an integral in terms of ( \theta ), which you can evaluate and then convert back to the original variable ( x ) to find the final answer.

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