# How do you find the integral of #dx/(1+x^2)#?

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To find the integral of ( \frac{dx}{1+x^2} ), you can use the arctangent integral formula, which states that:

[ \int \frac{1}{1+x^2} , dx = \arctan(x) + C ]

where ( C ) is the constant of integration. Therefore, the integral of ( \frac{dx}{1+x^2} ) is:

[ \int \frac{dx}{1+x^2} = \arctan(x) + C ]

where ( C ) is the constant of integration.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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