# How do you find the integral of #(cosx)^2/(sinx)#?

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To find the integral of ( \frac{{\cos^2(x)}}{{\sin(x)}} ), you can use the substitution method. Let ( u = \sin(x) ), then ( du = \cos(x) dx ). Substitute ( u ) and ( du ) into the integral, and rewrite the integral in terms of ( u ). You'll end up with ( \int \frac{{1 - u^2}}{{u}} du ). Divide ( u ) into ( 1 - u^2 ), and then integrate term by term. You will obtain ( \ln|\sin(x)| - \sin(x) + C ), where ( C ) is the constant of integration.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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