How do you find the integral of #cos^(2)3x dx#?
Emilia AguilarBy signing up, you agree to our Terms of Service and Privacy Policy
To find the integral of cos²(3x) dx, you can use the trigonometric identity:
cos²(x) = (1 + cos(2x))/2
So, for cos²(3x), it becomes:
(1 + cos(2*3x))/2
= (1 + cos(6x))/2
Now, integrate:
∫(1 + cos(6x))/2 dx
= (1/2) ∫(1 + cos(6x)) dx
= (1/2) ∫dx + (1/2) ∫cos(6x) dx
= (1/2) [x + (1/6)sin(6x)] + C
Where C is the constant of integration.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you write the definite integral to find the smaller area cut from the circle #x^2 + y^2 = 25# by the line x = 3?
- How do you integrate #dy / (4(y^(1/2))#?
- How do you integrate #int (t^2-sint)dt#?
- How do you integrate #int (1+3t)t^2dt#?
- How do you find the indefinite integral of #int (4sinx)/(3tanx)dx#?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7