How do you find the integral of #1/(2x) dx #?
It is
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To find the integral of ( \frac{1}{2x} ) with respect to ( x ), you can use the integral rule for logarithmic functions. The integral of ( \frac{1}{x} ) is ( \ln|x| ), so by applying this rule:
[ \int \frac{1}{2x} , dx = \frac{1}{2} \int \frac{1}{x} , dx ]
[ = \frac{1}{2} \ln|x| + C ]
Where ( C ) is the constant of integration. Therefore, the integral of ( \frac{1}{2x} ) with respect to ( x ) is ( \frac{1}{2} \ln|x| + C ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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