# How do you find the integral of #1/2+sinx dx #?

See below.

Finally, we can add together the constants and have our final answer as:

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To find the integral of ( \frac{1}{2} + \sin(x) ) with respect to ( x ), you would integrate each term separately. The integral of ( \frac{1}{2} ) with respect to ( x ) is ( \frac{1}{2}x ), and the integral of ( \sin(x) ) with respect to ( x ) is ( -\cos(x) ). Therefore, the integral of ( \frac{1}{2} + \sin(x) ) with respect to ( x ) is ( \frac{1}{2}x - \cos(x) + C ), where ( C ) is the constant of integration.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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