# How do you find the integral #(ln x)^2#?

I found:

I would try using Substitution and By Parts (twice):

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I get the same answer as Gio,

But the details of my solution are different.

Use integration by parts:

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Anyways, continuing on:

Cool, still got the same answer.

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To find the integral of (ln x)^2, you can use integration by parts. Let u = ln(x) and dv = ln(x) dx. Then differentiate u to get du and integrate dv to get v. After that, apply the integration by parts formula:

∫(ln(x))^2 dx = u*v - ∫v du

Substitute the values of u, v, du, and dv into the formula and perform the necessary calculations to find the integral.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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