How do you find the instantaneous velocity at #t=0# for the position function #s(t) = 6t^2 +8t#?

Answer 1

#8#

The position is given by the function #s(t)=6t^2+8t#.
The velocity is the rate of change of displacement over time, so it'll be the derivative of the position function, i.e. #v(t)=s'(t)=12t+8#.
So, at #t=0#, the instantaneous velocity will be:
#s'(0)=12*0+8#
#=0+8#
#=8#
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Answer 2

To find the instantaneous velocity at t = 0 for the position function s(t) = 6t^2 + 8t, you need to find the derivative of the position function with respect to time (s'(t)), and then evaluate it at t = 0.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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