# How do you find the indefinite integral of #int (x^2-3x+2)/(x-1) dx#?

The function is

I would recommend factoring the numerator and the denominator to see if we can eliminate/simplify before integrating.

You can always verify your answer by differentiating. You will see the integration worked.

Hopefully this helps!

By signing up, you agree to our Terms of Service and Privacy Policy

To find the indefinite integral of ( \int \frac{x^2 - 3x + 2}{x - 1} , dx ), you can use polynomial long division to divide ( x^2 - 3x + 2 ) by ( x - 1 ), which will give you the quotient ( x - 2 ) and a remainder of ( 0 ). Then integrate the resulting expression. The indefinite integral is:

[ \int \frac{x^2 - 3x + 2}{x - 1} , dx = \int (x - 2) , dx ]

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you find the sum of the infinite series #Sigma(1/10)^k# from k=1 to #oo#?
- What is #int ln4x^2dx#?
- What is the antiderivative of #e^(-3x)#?
- How do you use sigma notation to write the sum for #1/(1*3)+1/(2*4)+1/(3*5)+...+1/(10*12)#?
- How do you integrate #(5x)/(2x^2+11x+12)# using partial fractions?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7