# How do you find the indefinite integral of #int (e^(x+3)+e^(x-3))dx#?

Add a constant at the end.

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To find the indefinite integral of (\int (e^{x+3} + e^{x-3}) , dx), you can integrate each term separately using the properties of integrals:

[ \int e^{x+3} , dx + \int e^{x-3} , dx ]

For ( \int e^{x+3} , dx ), perform a substitution, let ( u = x + 3 ).

For ( \int e^{x-3} , dx ), perform a substitution, let ( v = x - 3 ).

Then integrate each term separately with respect to their respective substitutions. After integration, revert back to the original variables.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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