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How do you find the indefinite integral of #int 5e^x-e#?

Answer 1

Emilia Aguilar

#5e^x -e x + C #

#int \ 5e^x-e \ dx #

#= 5e^x -e x + C #

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Answer 2

Emily Ammerman

To find the indefinite integral of (\int (5e^x - e) , dx), you integrate each term separately:

[ \int 5e^x , dx - \int e , dx ]

The integral of (5e^x) with respect to (x) is (5e^x). The integral of (e) with respect to (x) is simply (e).

So, putting it all together:

[ \int (5e^x - e) , dx = 5e^x - e + C ]

Where (C) is the constant of integration.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.