# How do you find the indefinite integral of #int -(35x^(2/5))/5dx#?

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To find the indefinite integral of ( -\frac{35x^{2/5}}{5} , dx ), you can use the power rule for integration. The power rule states that the integral of ( x^n , dx ) is ( \frac{x^{n+1}}{n+1} ), where ( n ) is not equal to -1. Applying this rule to the given function:

[ \int -\frac{35x^{2/5}}{5} , dx = -\frac{35}{5} \cdot \int x^{2/5} , dx ]

[ = -7 \cdot \frac{x^{2/5 + 1}}{2/5 + 1} + C ]

[ = -7 \cdot \frac{x^{7/5}}{7/5} + C ]

[ = -\frac{5x^{7/5}}{5} + C ]

[ = -x^{7/5} + C ]

Therefore, the indefinite integral of ( -\frac{35x^{2/5}}{5} , dx ) is ( -x^{7/5} + C ), where ( C ) is the constant of integration.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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