# How do you find the horizontal asymptote of the graph of #y=(-4x^6+6x+3)/(8x^6+9x+3)# ?

How do you find the horizontal asymptote of a curve?

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To find the horizontal asymptote of the graph of y=(-4x^6+6x+3)/(8x^6+9x+3), we need to compare the degrees of the numerator and denominator polynomials. In this case, both the numerator and denominator have a degree of 6.

When the degrees of the numerator and denominator are equal, the horizontal asymptote can be determined by dividing the leading coefficients of the polynomials. In this case, the leading coefficient of the numerator is -4 and the leading coefficient of the denominator is 8.

Dividing -4 by 8, we get -1/2. Therefore, the horizontal asymptote of the graph is y = -1/2.

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