How do you find the horizontal asymptote of the graph of #y=(-4x^6+6x+3)/(8x^6+9x+3)# ?

Answer 1
Please follow the explanation of the link below. Your answer will be #y=-1/2#

How do you find the horizontal asymptote of a curve?

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Answer 2

To find the horizontal asymptote of the graph of y=(-4x^6+6x+3)/(8x^6+9x+3), we need to compare the degrees of the numerator and denominator polynomials. In this case, both the numerator and denominator have a degree of 6.

When the degrees of the numerator and denominator are equal, the horizontal asymptote can be determined by dividing the leading coefficients of the polynomials. In this case, the leading coefficient of the numerator is -4 and the leading coefficient of the denominator is 8.

Dividing -4 by 8, we get -1/2. Therefore, the horizontal asymptote of the graph is y = -1/2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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