# How do you find the horizontal asymptote for # (3x^4 + 2x +1) / (100x^3 + 2)#?

Horizontal asymptotes only occur when the numerator degree is equal or less than denominator

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To find the horizontal asymptote of the function ( \frac{3x^4 + 2x + 1}{100x^3 + 2} ), divide the leading term of the numerator by the leading term of the denominator. In this case, it's ( \frac{3x^4}{100x^3} ). After simplifying, the horizontal asymptote is ( y = \frac{3}{100x} ).

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