How do you find the first and second derivatives of #y = (x^2 + 3) / e^-x# using the quotient rule?
Alternatively, you could rewrite the original question as a product and apply the product rule instead of the quotient rule.
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To find the first and second derivatives of ( y = \frac{x^2 + 3}{e^{-x}} ) using the quotient rule:
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First, let's denote ( u = x^2 + 3 ) and ( v = e^{-x} ).
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Then, we'll find the derivatives of ( u ) and ( v ):
( u' = 2x )
( v' = -e^{-x} )
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Next, we'll apply the quotient rule, which states that for functions ( u(x) ) and ( v(x) ), the derivative of their quotient is:
( \frac{d}{dx}\left(\frac{u}{v}\right) = \frac{u'v - uv'}{v^2} )
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Now, using the quotient rule, we have:
( \frac{d}{dx}\left(\frac{u}{v}\right) = \frac{(2x)(e^{-x}) - (x^2 + 3)(-e^{-x})}{(e^{-x})^2} )
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Simplifying this expression gives us the first derivative:
( \frac{d}{dx}\left(\frac{x^2 + 3}{e^{-x}}\right) = \frac{2xe^{-x} + (x^2 + 3)e^{-x}}{e^{-2x}} )
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To find the second derivative, we need to differentiate the first derivative again with respect to ( x ):
( \frac{d^2}{dx^2}\left(\frac{x^2 + 3}{e^{-x}}\right) = \frac{d}{dx}\left(\frac{2xe^{-x} + (x^2 + 3)e^{-x}}{e^{-2x}}\right) )
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Simplify the expression obtained from the first derivative and then apply the quotient rule again to find the second derivative.
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After simplifying the expression obtained for the second derivative, you'll have the result.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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