# How do you find the first and second derivative of #ln(x/20)#?

Based on the properties of logarithms:

so that:

By signing up, you agree to our Terms of Service and Privacy Policy

We use the Rule

By signing up, you agree to our Terms of Service and Privacy Policy

To find the first derivative of ln(x/20), apply the chain rule: (1/(x/20))*(1/20). Simplify to get 1/x.

To find the second derivative, differentiate the first derivative: -1/x^2.

By signing up, you agree to our Terms of Service and Privacy Policy

- Consider the curve #y = (x^2- 2x+k)(x-6)^2 #, where #k# is a real constant. The curve has a maximum point at # x =3#. What is the value of #k#?
- What are the points of inflection, if any, of #f(x)= x^5 -2 x^3 - x^2-2 #?
- If #y = 3x^5 - 5x^3#, what are the points of inflection of the graph f (x)?
- What are the points of inflection of #f(x)=x^7/(4x-2) #?
- For what values of x is #f(x)=3x^3+2x^2-x+9# concave or convex?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7