How do you find the (f o g o h) (x) for #f(x)=(x2)/(2x+1), #g(x)=3x+1#, #h(x)=x^2#?
To find (f o g o h)(x) for the given functions ( f(x) = \frac{x2}{2x+1} ), ( g(x) = 3x+1 ), and ( h(x) = x^2 ), follow these steps:

First, find ( (f o g)(x) ) by substituting ( g(x) ) into ( f(x) ): ( f(g(x)) = f(3x+1) = \frac{(3x+1)2}{2(3x+1)+1} )

Next, find ( (f o g o h)(x) ) by substituting ( h(x) ) into ( f(g(x)) ): ( (f o g o h)(x) = f(g(h(x))) = f(g(x^2)) = \frac{(3x^2+1)2}{2(3x^2+1)+1} )
Simplify the expression to get the final answer.
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In this problem, ƒ o g o h = ƒ(g(h(x)))
Start out by plugging h into g.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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