# How do you find the excluded values of #\frac{2x+1}{x^2-x-6}#?

Since there can be no zero denominators, we have

By adjusting for,

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To find the excluded values of the expression \frac{2x+1}{x^2-x-6}, we need to determine the values of x that would make the denominator equal to zero.

The denominator of the expression is x^2-x-6. To find the values of x that make the denominator zero, we can set the denominator equal to zero and solve for x.

Setting x^2-x-6 equal to zero, we can factor the quadratic equation as (x-3)(x+2) = 0.

This means that either (x-3) = 0 or (x+2) = 0.

Solving these equations, we find that x = 3 or x = -2.

Therefore, the excluded values of the expression \frac{2x+1}{x^2-x-6} are x = 3 and x = -2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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