# How do you find the excluded value of #3/(x-5)#?

I got

By signing up, you agree to our Terms of Service and Privacy Policy

To find the excluded value of 3/(x-5), we need to determine the value(s) of x that would make the denominator, (x-5), equal to zero. Setting the denominator equal to zero and solving for x, we have:

x - 5 = 0

Adding 5 to both sides:

x = 5

Therefore, the excluded value of 3/(x-5) is x = 5.

By signing up, you agree to our Terms of Service and Privacy Policy

- What are the asymptotes of #y=-2/(x+1)# and how do you graph the function?
- Suppose that the time it takes to do a job is inversely proportional to the number of workers. That is, the more workers on the job the less time required to complete the job. Is it takes 2 workers 8 days to finish a job, how long will it take 8 workers?
- How do you simplify #(80x^4)/y^4*(xy)/(5x^2)#?
- How do you divide #(-x^3 - x^2-6x+5 )/((-x + 10 )#?
- How do you write a general formula to describe each variation if the cube of z varies directly with the sum of the squares of x and y; z=2 when x=9 and y=4?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7