How do you find the excluded value and simplify # (3x^2-5x-28)/(x^2+3x-28)#?

Answer 1

#(3x+7)/(x+7)#

#(3x^2-5x-28)/(x^2+3x-28)#
=#(3x^2-12x+7x-28)/(x^2+7x-4x-28)#
=#[3x*(x-4)+7*(x-4)]/[x*(x+7)-4*(x+7)]#
=#[(3x+7)(x-4)]/[(x-4)(x+7)]#
=#(3x+7)/(x+7)#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

#=(3x+7)/(x+7) = 1 + (2x)/(x+7)#

#Nr = 3x^2-5x-28= 3x^2-12x+7x-28# #=3x(x-4)+7(x-4) = (x-4)(3x+7)#
#Dr = x^2+3x-28=x^2+7x-4x-28# #=x(x+7)-4(x+7)=(x-4)(x+7)#
#Nr/Dr = (cancel(x-4)(x+7)) /(cancel(x-4)(4x+7)#
#=(3x+7)/(x+7) = 1 + (2x)/(x+7)#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 3

To find the excluded value, we need to determine the values of x that would make the denominator equal to zero. In this case, the denominator is (x^2+3x-28). To find the excluded value, we set the denominator equal to zero and solve for x.

(x^2+3x-28) = 0

Factoring the quadratic equation, we have:

(x+7)(x-4) = 0

Setting each factor equal to zero, we get:

x+7 = 0 or x-4 = 0

Solving for x, we find:

x = -7 or x = 4

Therefore, the excluded values are x = -7 and x = 4.

To simplify the expression (3x^2-5x-28)/(x^2+3x-28), we can divide both the numerator and denominator by the greatest common factor (GCF) of the terms. In this case, the GCF is 1.

Simplifying the expression, we get:

(3x^2-5x-28)/(x^2+3x-28) = (3x^2-5x-28)/(x+7)(x-4)

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 4

To find the excluded value for the expression (3x^2 - 5x - 28) / (x^2 + 3x - 28), we need to determine the values of x that would make the denominator zero, as division by zero is undefined. To find these values, we set the denominator equal to zero and solve for x.

The denominator is x^2 + 3x - 28. Setting this expression equal to zero, we get:

x^2 + 3x - 28 = 0

Now, we can factor the quadratic equation or use the quadratic formula to solve for x.

Factoring: (x + 7)(x - 4) = 0

Setting each factor equal to zero: x + 7 = 0 --> x = -7 x - 4 = 0 --> x = 4

So, the excluded values for this expression are x = -7 and x = 4.

To simplify the expression, we can factor both the numerator and the denominator, then cancel out common factors if they exist. After that, we rewrite the expression in its simplest form.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7