# How do you find the exact value of #tan^-1sqrt3#?

This can either equal

First of all, you need to find the quadrants where tangent is positive. You can remember the signs of the trigonometric functions in the quadrants using the following rule.

Tangent is positive in quadrants

Now take the special triangle possessing sides of length

In the special triangle, the angle of

We mentioned earlier that tangent is positive in quadrants

Hopefully this helps!

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To find the exact value of (\tan^{-1}(\sqrt{3})), you can use the relationship between trigonometric functions. Since (\tan(\frac{\pi}{3}) = \sqrt{3}), it follows that (\tan^{-1}(\sqrt{3}) = \frac{\pi}{3}). Therefore, the exact value of (\tan^{-1}(\sqrt{3})) is (\frac{\pi}{3}).

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