# How do you find the exact value of #Sin^-1(cos(pi/4))#?

Question writers, questions like this are your big chance to get away from the two cliche triangles of trig.

Of course,

#text{Arc}text{sin}(cos (pi/4) ) = text{Arc}text{sin}( 1/sqrt{2} ) = pi/4

We can rewrite that as

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To find the exact value of sin^-1(cos(pi/4)), you can use the identity sin^-1(cos(x)) = x for 0 ≤ x ≤ π.

Given cos(pi/4) = √2 / 2, sin^-1(√2 / 2) = π/4. Therefore, the exact value of sin^-1(cos(pi/4)) is π/4.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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