Home > Trigonometry > Basic Inverse Trigonometric Functions

How do you find the exact value of #cot^-1(-sqrt3)#?

Answer 1

Delilah Aguilar

#cot^(-1)(-sqrt3)=-pi/6#

The range for #cot^(-1)x# is from #-pi/2# to #pi/2#

As #cot(-pi/6)=-sqrt3#

#cot^(-1)(-sqrt3)=-pi/6#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Victoria Adebayo

To find the exact value of cotangent inverse of negative square root of 3, we can use the fact that cotangent is the reciprocal of tangent. Thus, cotangent inverse of a value is the same as the inverse tangent of the reciprocal of that value. In this case, cotangent inverse of negative square root of 3 would be equivalent to the inverse tangent of negative 1 over square root of 3. The inverse tangent of negative 1 over square root of 3 is equal to negative pi over 6 radians or negative 30 degrees. Therefore, cotangent inverse of negative square root of 3 is negative pi over 6 radians or negative 30 degrees.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.