How do you find the equation of the line #y = x^3 - 5x^2 + 2x +1# tangent to the curve and its point of inflection?

Answer 1

The equation of the line is #y=-19/3x+152/27#

Let #f(x)=x^3-5x^2+2x+1#

Taking the first derivative

#f'(x)=3x^2-10x+2#

Taking the second derivative

#f''(x)=6x-10#
The point of inflection is when #f''(x)=0#
#6x-10=0#, #=>#, #x=10/6=5/3#
The slope of the curve when #x=5/3# is
#f'(5/3)=3*(5/3)^2-10*5/3+2=25/3-50/3+2=-25/3+2=-19/6#
When #x=5/3#, #=>#
#f(5/3)=(5/3)^3-5*(5/3)^2+10/3+1=125/27-125/9+10/3+1#
#=(125-375+90+27)/27=-133/27#
The eqaution of the tangent at the point #=(5/3, -133/27)# is
#y-f(5/3)=f'(5/3)(x-5/3)#
#y+133/27=-19/3(x-5/3)#
#y=-19/3x+95/9-133/27=-19/3x+152/27#

graph{(y-x^3+5x^2-2x-1)(y+19/3x-152/27)=0 [-18.56, 21.99, -14, 6.28]}

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Answer 2

To find the equation of the line tangent to the curve y = x^3 - 5x^2 + 2x + 1 at its point of inflection, we need to follow these steps:

  1. Find the derivative of the curve equation to obtain the slope function.
  2. Set the derivative equal to zero and solve for x to find the x-coordinate of the point of inflection.
  3. Substitute the x-coordinate of the point of inflection into the original curve equation to find the y-coordinate.
  4. Use the slope function and the coordinates of the point of inflection to determine the slope of the tangent line.
  5. Use the point-slope form of a line to write the equation of the tangent line.

Let's go through these steps:

  1. Differentiate the curve equation: y' = 3x^2 - 10x + 2.

  2. Set the derivative equal to zero and solve for x: 3x^2 - 10x + 2 = 0.

  3. Solve the quadratic equation to find the x-coordinate of the point of inflection.

  4. Substitute the x-coordinate of the point of inflection into the original curve equation to find the y-coordinate.

  5. Use the slope function and the coordinates of the point of inflection to determine the slope of the tangent line.

  6. Use the point-slope form of a line to write the equation of the tangent line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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