How do you find the equation of the line through the point (6 , -1) and is perpendicular to the y axis?

Answer 1

The equation would be #y=-1#.

Since the line is perpendicular to the #y#-axis, it will be a horizontal line that runs through #(6,-1)#.
In this case, the #x#-coordinate doesn't matter; no matter what, if the line is horizontal to the #y#-axis, it will be horizontal, and thus it will be the same value regardless of the #x#-value.
In this case, the #y#-value is #-1# throughout the line.
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Answer 2

#y=-1#

A horizontal line is one that is perpendicular to the y axis, and its equation is y=b, where b is the y-intercept.

In this case the line goes through the point #(x,y) = (6,-1)# so it has a y value of -1 since the line is horizontal that y value must also be the y intercept so the equation is:
#y=-1#
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Answer 3

To find the equation of the line through the point (6, -1) and perpendicular to the y-axis, we recognize that any line perpendicular to the y-axis is parallel to the x-axis. Therefore, the equation of the line passing through the point (6, -1) and parallel to the x-axis is simply (y = -1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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