How do you find the equation of the line tangent to #f(x)= 1/x#, at (1/2,2)?

Answer 1

#y-2=-4(x-1/2)#
#y=-4x+4#

#f'(x)=-1/x^2# #f'(1/2)=-1/(1/4) = -4# #y-2=-4(x-1/2)# #y=-4x+4#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

#4x+y=4#

If #color(white)("XXX")f(x)=1/x=x^(-1)# then #color(white)("XXX")f'(x)=(-1)(x^(-2)) = -1/x^2#
At #(color(red)(1/2),2)# the slope of the tangent line is #color(white)("XXX")f'(color(red)(1/2))=-1/((color(red)(1/2))^2) = color(green)(-4)#
The slope-point form of the tangent line using a slope of #color(green)(m=-4)# and the point #(color(red)(barx),color(blue)(bary)) =(color(red)(1/2),color(blue)(2))# is #color(white)("XXX")y-color(blue)(bary)=color(green)(m)(x-color(red)(barx))#
or, with the given values: #color(white)("XXX")y-color(blue)(2=color(green)(-4)(x-color(red)(1/2))# #rarr# #color(white)("XXX")y-2 = -4x +2# in standard form: #color(white)("XXX")4x+y=4#

graph{(1/x-y)(4x+y-4)=0 [-3.973, 4.8, -1.268, 3.117]}

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 3

To find the equation of the line tangent to the function f(x) = 1/x at the point (1/2, 2), we can use the concept of differentiation.

First, we need to find the derivative of the function f(x). The derivative of 1/x can be found using the power rule for differentiation, which states that the derivative of x^n is n*x^(n-1). Applying this rule, the derivative of 1/x is -1/x^2.

Next, we substitute the x-coordinate of the given point (1/2, 2) into the derivative to find the slope of the tangent line. Plugging in x = 1/2 into the derivative -1/x^2, we get -1/(1/2)^2 = -1/(1/4) = -4.

Now that we have the slope of the tangent line, we can use the point-slope form of a linear equation to find the equation of the line. The point-slope form is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope. Substituting the values x1 = 1/2, y1 = 2, and m = -4, we get y - 2 = -4(x - 1/2).

Simplifying the equation, we have y - 2 = -4x + 2. Rearranging the terms, we get the equation of the line tangent to f(x) = 1/x at (1/2, 2) as y = -4x + 4.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7