# How do you find the equation of tangent line to the curve # f(x) = 9tanx# at the point #(pi/4, f(pi/4)) #?

graph{(36x-2y+18-9pi)(y-9tanx)=0 [-4, 4, -20, 20]}

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To find the equation of the tangent line to the curve f(x) = 9tanx at the point (pi/4, f(pi/4)), we need to find the derivative of f(x) and evaluate it at x = pi/4. The derivative of f(x) = 9tanx is f'(x) = 9sec^2x. Evaluating f'(x) at x = pi/4, we get f'(pi/4) = 9sec^2(pi/4) = 9(2^2) = 36. Therefore, the slope of the tangent line is 36. Using the point-slope form of a line, the equation of the tangent line is y - f(pi/4) = 36(x - pi/4).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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